Program to find the transpose of m*n Matrix | C++ Programming
Tuesday, August 11, 2020
//Program to find the transpose of m*n Matrix
#include<iostream.h>
#include<conio.h>
void main()
{clrscr();
int A[10][10],B[10][10],m,n,i,j;
cout<<"\n Enter The No. of rows :";
cin>>m;
cout<<"\n Enter The No. of columns :";
cin>>n;
for(i=0; i<m;i++)
{for(j=0; j<n;j++)
{cout<<"\n Enter A["<<i<<"]["<<j<<"] element :";
cin>>A[i][j];
}
}
cout<<"\n The Matrix is :";
for(i=0;i<m;i++)
{cout<<"\n";
for(j=0;j<n;j++)
cout<<A[i][j]<<" ";
}
for(i=0;i<n;i++)
{for(j=0;j<m;j++)
B[i][j]=A[j][i];
}
cout<<"\n The Transpose Matrix Is :";
for(i=0;i<n;i++)
{cout<<"\n";
for(j=0;j<m;j++)
cout<<B[i][j] <<"";
}
getch();
}
#include<iostream.h>
#include<conio.h>
void main()
{clrscr();
int A[10][10],B[10][10],m,n,i,j;
cout<<"\n Enter The No. of rows :";
cin>>m;
cout<<"\n Enter The No. of columns :";
cin>>n;
for(i=0; i<m;i++)
{for(j=0; j<n;j++)
{cout<<"\n Enter A["<<i<<"]["<<j<<"] element :";
cin>>A[i][j];
}
}
cout<<"\n The Matrix is :";
for(i=0;i<m;i++)
{cout<<"\n";
for(j=0;j<n;j++)
cout<<A[i][j]<<" ";
}
for(i=0;i<n;i++)
{for(j=0;j<m;j++)
B[i][j]=A[j][i];
}
cout<<"\n The Transpose Matrix Is :";
for(i=0;i<n;i++)
{cout<<"\n";
for(j=0;j<m;j++)
cout<<B[i][j] <<"";
}
getch();
}
0 Comments