Program to display the sum of each row elements
Tuesday, August 11, 2020
//Program to display the sum of each row elements
#include<iostream.h>
#include<conio.h>
#include <math.h>
void main()
{ clrscr();
int P[10][10],m,n,i,j,sum1=0;
cout<<"\n enter the no of rows for P:";
cin>>m;
cout<<"\n enter the no of columns for P:";
cin>>n;
for(i=0;i<m;i++)
{
for(j=0;j<n;j++)
{
cout<<"\n enter P["<<i<<"]["<<j<<"] elements:";
cin>>P[i][j];
}
}
cout<<"\n the matrix P is:";
for (i=0;i<m; i++)
{cout<<"\n";
for(j=0; j<n; j++)
cout<<P[i][j]<<" ";
}
for(i=0;i<m; i++)
{sum1=0;
for(j=0; j<n; j++)
sum1+=P[i][j];
cout<<"\n Sum of row"<<i+1<<"="<<sum1;
}
getch();
}
#include<iostream.h>
#include<conio.h>
#include <math.h>
void main()
{ clrscr();
int P[10][10],m,n,i,j,sum1=0;
cout<<"\n enter the no of rows for P:";
cin>>m;
cout<<"\n enter the no of columns for P:";
cin>>n;
for(i=0;i<m;i++)
{
for(j=0;j<n;j++)
{
cout<<"\n enter P["<<i<<"]["<<j<<"] elements:";
cin>>P[i][j];
}
}
cout<<"\n the matrix P is:";
for (i=0;i<m; i++)
{cout<<"\n";
for(j=0; j<n; j++)
cout<<P[i][j]<<" ";
}
for(i=0;i<m; i++)
{sum1=0;
for(j=0; j<n; j++)
sum1+=P[i][j];
cout<<"\n Sum of row"<<i+1<<"="<<sum1;
}
getch();
}
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